Q: Find out the peak load voltage for the circuit shown in the diagram.
SOLUTION:
Primary, the ac input to the transformer is changed to a peak value, like follows
V1(pk) = V1rms/0.707
= 120/0.707= 169.7Vpk
Now, in the secondary circuit the voltage values are determined as
V2(pk) = N2/N1(V1pk)
= 1/5(169.7)
V2(pk )= 33.94Vpk
As well as
VLpk = V2(pk) - VF
Diode is a silicon diode
= 33.94 - 0.7
VLpk = 33.24Vpk