A steel specimen represents upper yield point at 210 MPa and lower yields point at200 MPa. If modulus of elasticity, E, for steel is 210 × 10³ MPa. Compute modulus of resilience.

Solution

Modulus of resilience = σ²_Y/2E

Here, σY is yield strength. σ_Y consequent to lower yield point. Thus σ_Y  = 200 MPa

∴    Modulus of resilience =((200)² × (106 )²) / 2 × 21⁰ × 103 × 10⁶ N-m/m³

Here note that MPa = Pa × 10⁶ = (N/m²  (10)⁶))

∴    Modulus resilience = 95.24 × 10⁴ N-m/m³

Otherwise       95.24 × 10^-3 N-mm/mm³