Q:  Determine the value of voltage Vo by using Thevenin's theorem .

Solution:

            We have to calculate V₀ by using Thevenin's theorem .For this we will follow the steps given earlier.

Step 1:      Removing R_L

Here R_L is 6k resistor at which we desire to calculate the value of voltage V_o.

Step 2:  Calculating the value of V_th

1k is in series to 2k so altered circuit will be as

3k is in parallel to 2mA source, therefore by source transformation

In the circuit 2mA source is in parallel to 3k resistor. Therefore it can be altered to a voltage source having value = 2m x 3k (ohm's Law)

                                                         = 6 V

3k resistor is now in series with this source as indicated in the following circuit

Now the join effect of these two sources is 9 V.

Therefore V_th = 9 V

Step 3:  Calculating the value of R_th

                                                            R_th = 3k

Step 4: Determining the unknown quantity.

After determining V_th & R_th, re-inserting the load resistance R_L in the circuit in series along R_th and letting the V_th like a battery in series with these two resistances.

                                                            V₀ = (6k/9k) x9

                                                             V₀= 6V