Chemical equilibria Assignment Help

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Chemical equilibria

A chemical  reaction  commonly  exists  in a state  of dynamic  equilibrium,  where while  new molecules  of product    and substrate are continually  being formed and transformed ,  the  ratio  of  substrate  to  product  remains  at  a  constant value.

Consider the reaction:

                                                            817_Chemical equilibria.png

where the rate of the further reaction is 10-4 per second (s-1) and the rate of the reverse reaction is 10-6  s-1. By equilibrium the ratio of the concentrations of the substrate   and product   gives a constant   value   which is called as the equilibrium K constant. The equilibrium constant for a given reaction is shown as:

 

                                             1866_Chemical equilibria 1.png

where square  brackets  shows  concentration.  Equilibrium constant is also given through the ratio of the forward reaction rate (kf) and the reverse reaction rate (kb):

                                              433_Chemical equilibria 2.png

Therefore, for the above reaction at equilibrium, there is 100 times more product of B than there is of substrate A, apart from of whether there is enzyme present or not present. This is because enzymes do not alter the equilibrium position of a reaction,

                          666_Chemical equilibria 3.png

Figure: Structure of adenosine triphosphate (ATP), adenosine diphosphate (ADP), adenosine monophosphate (AMP) and adenosine.


but  accelerate  the  reverse  and forward  reactions  to the  similar  extent.  Alternatively, enzymes accelerate the attainment of the equilibrium position but do not shift its position. For the hypothetical  reaction described above, in the absence of added enzyme  the reaction  may take over an hour to reach the equilibrium position,  while  in the presence  of enzyme  the equilibrium  position  may be reached in less than 1 s.

 

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