Q:  Determine Io in the given circuit.

Solution:         

            Applying KCL equation at node 1

                        ((V₁ - 6)/4k) + ((V₁ - 12)/2k) +(V₁/10k) = 0

                                           5V₁ - 30 + 2V₁ +10V₁ - 120 = 0

                                              17 V₁ = 150

                                               V₁ = 8.82 V

                                                 I₀ = (V₁- 12)/2k

                                                = (8.82 - 12)/2k = - 1.58 mA

            Therefore the current value is in negative sign, thus we conclude that like this is given in the given circuit the direction of current Io is opposite.