Find Total force:
A single cylinder vertical engine contains a bore 35 cm and a stroke of 40 cm. The connecting rod is equal to 110 cm long. Mass of reciprocating parts is equal to 140 kg. At the expansion stroke along the crank at 30o from the TDC, the gas pressure is equal to 0.8 MPa. If engine runs at 260 rpm, find Total force at the piston,
Solution
It is given that:
Piston diameter, d = 35 cm = 0.35 m
Piston stroke, s = 40 cm = 0.4 m
Length of CR, l = 110 cm
Mass of reciprocating points, 'm' = 140 kg
Pressure in cylinder, 'p' = 0.8 MPa
Speed, 'N' = 260 rpm
Angle θ = 30o
Net Force on the Piston
To calculate Net force on the piston of a vertical engine
P = Gas force ± Inertia force + Load
Gas force = (π/4) d 2 p = (π/4) (0.35)2 × 0.8 × 106 N = 76969 N
Inertia force = m ω2 r =
Inertia force = 140 × (27.23)2 × 0.2 ( cos 30o + (cos 60)/55 ) = 19867 N
Load 'W ' = 140 g = 1373.4 N
Net force on the piston
P = 76969 - 19867 + 1373.4 = 58475 N