Calculate Voltage by using Source Transformation Method Assignment Help

Assignment Help: >> Source Transformation - Calculate Voltage by using Source Transformation Method

Q:  Compute the voltage Vo applying source transformation method.

2449_potential.png

Solution:

We have to calculate the voltage Vo utilizing source transformation method. We will further proceed as

 In the circuit 3k is in series with 12 volts battery. Therefore it may be converted into a current source having value =12/3k   (by using ohm's Law)

                                      =4mA

            Now voltage source is converted in the current source as indicated below

542_potential1.png

             In the circuit 3k resistor is in parallel along 6k resistor therefore

                                                   3k||6k = (3k x6k)/3k +6k

                                                             = 2k

            We will now replace 3k & 6k resistance with 2k as indicated in the following circuit

2164_potential2.png

            4mA source is parallel along 2k resistor. Therefore it can be converted into a voltage source. By applying ohm's Law we get the value of voltage source = 8 volts which will be in series from resistor of 2k, so our altered circuit will be  like

2246_potential3.png

            In the above shown circuit 2k is in series from 2k so altered circuit will be like

2015_potential4.png

8volt source is in series from 4k resistor. Therefore it may be converted into a current source of value    = 8/4k (Ohm's Law)

                  = 2mA

 2mA current source is in parallel from 4k

Our altered circuit will be like

1344_potential5.png

 In the above shown circuit two sources of current are parallel to each other, so current sources will sum up to give value of 4mA.

            Our altered circuit will be like

1657_potential6.png

In the above shown circuit 4mA source is in parallel to 4k resistor .therefore it might be transformed into a voltage source having value 16volts by using Ohm's Law. Our altered circuit will be

360_potential7.png

            In the above indicated circuit 4k & 4k are in series therefore our altered circuit will be as

1419_potential8.png

Now we will apply voltage division rule

1258_potential9.png

                                                V0 =  8k/16k   x 16V

                                                              V0 = 8V           Ans.

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