Limiting ionic conductivities:

The limiting ionic conductivities can be obtained from the literature, the solubility c of a sparingly soluble salt can therefore be determined from conductivity values. Once c is known the solubility product can also be calculated as follows.

Consider the sparingly soluble salt solution of AgCl. The limited molar conductivities of its ions Ag⁺ and Cl^-, are 0.00619 S m² mol^-1 and 0.00763 S m² mol^-1 respectively. The conductivity of AgCl solution at 298 K is measured to be 2.28 × 10-4 S m^-1. To calculate solubility product, first calculate concentration of Ag⁺ and Cl^- ions in the solution using Eq. ,

 c  =     κ _AgCl/ Λ _Ag+^∝ +Λ _Cl-^∝

=2.28×10^-4 S m ^-1/(0.00619 + 0.00763) S m ² mol ^-1

= 1.65×10^-2 mol m ^-3

= 1.65×10 ^-5 mol dm ^-3