Find the amplitude of vibration of the machine:

A machine containing weigh 1000 kg is mounted on the floor identical spring with stiffness of each spring equivalent to 'k'. The machine is excited by a harmonic force along amplitude 500 N and frequency is 200 rpm. Find the amplitude of vibration of the machine for k = 0.5 × 106 N/m. Neglect damping.

Solution

It is given that

F_o = 500 N

Total stiffness = 4k = 4 × 0.5 × 106 = 2.0 × 106 N/m

Mass = 1000 kg

∴             ω= (2π 200)/60 = 20.94 r/s

                            X = 0.32 mm