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Q. Simplify the given circuit.
Solution: 4k Ω is parallel having 4k Ω so 4k||4k = (4 x 4)/(4 +4)
=16/8
= 2k Ω
2kΩis parallel with 2k Ω.
So Req= (2 x2)/(2 +2) = 4/4
=1 KΩ
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