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Replacement Policy When Money Value Does Not Change With Time

Let us now find the optimal policy for the case of replacement when money value does not change with time.

Let C = capital or purchase cost of new item.

S = scrap or salvage or resale value of the item at the end of 'n' or't' years.

Rn or R (t) = running (or operating) cost for the year 'n' or't'.

n or t = replacement age of the equipment. Here two cases arise

Case I

When time t is continuous variable:

If the equipment is used for't' years, then the total cost incurred over this period is given by

Tc = capital (or purchase) cost - scrap value at the end of t years + running cost for t years.

1679_Replacement Policy When Money Value Does Not Change 1.png

There fore average cost per unit time incurred over the period of n years is

 Equation 1            

544_Replacement Policy When Money Value Does Not Change 2.png

To obtain optimal value of n for which ATCn is minimum, differentiate ATCn with respect to n and set the first derivative equal to zero, i.e. minimum of ATCn.

2052_Replacement Policy When Money Value Does Not Change 3.png

or

1873_Replacement Policy When Money Value Does Not Change 4.png

 Equation 2

           R (n) = ATCn    

Hence the following replacement policy can be derived with the help of Eq. (2).

Policy

Replace the equipment when the average annual cost for n years becomes equal to the current/running cost.

i.e.  Equation 3 

2477_Replacement Policy When Money Value Does Not Change 5.png

Case II

When time t is a discrete variable :

The average cost incurred over the period n is given by

715_Replacement Policy When Money Value Does Not Change 6.png

 If C - S and 520_Replacement Policy When Money Value Does Not Change 7.png  are assumed to be monotonically decreasing and increasing respectively, then there will exist a value of n for which ATCn is minimum. Thus we shall have inequalities

ATCn -1  > ATCn +1

ATCn -1  - ATCn  > 0

Rewriting Eq. (3) for period n + 1, we get

601_Replacement Policy When Money Value Does Not Change 8.png

743_Replacement Policy When Money Value Does Not Change 9.png

Therefore,

ATCn +1 - ATCn = (n/ n + 1) ATCn + (R(n+1) /(n+1)) - ATCn

= (R (n + 1) / (n+1)) + ATCn [(n/ (n+1)) - 1]

= R (n + 1) / (n+1) - ATCn / (n+1)

Since ATCn + 1 - ATCn > 0, we get

R (n + 1)/ (n + 1) - ATCn  /(n+1)  > 0

i.e.  R (n + 1) - ATCn > 0

or R (n + 1) > ATCn

Similarly ATCn - 1 - ATCn > 0 implies that R (n) < ATCn - 1

This provides the following replacement policy.

Policy 1

If the next year, running cost, R (n + 1) is more than average cost of nth year, ATCn then it is economical to replace at the end of n years

i.e.

1532_Replacement Policy When Money Value Does Not Change 11.png

Policy 2

If the present year's running cost is less than the previous year's average cost, ATCn - 1 then do not replace.

i.e.

1391_Replacement Policy When Money Value Does Not Change 10.png

Algorithm of Replacement Policy When Money Value Does Not Change
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