Fixed End Moment:
As there are no loads on columns AB and CD, there will not be any fixed moments at their ends. However, the beam member BC will have fixed end moments.
M FBC = - wl2/12 = -(2x62/12) = -0.6 kNm; MFCB = +6.0 kNm.
There are no sway moments as a frame and loading is symmetrical.