Q: Find the voltage across 4kΩ resistor in given figure.
Solution:
We have to calculate the voltage across 4kΩ resistor.
12k||4k = (12 x4)/ (12+4)
= 3kΩ
9kΩ is in series along 3kΩ their joint effect = (9k +3k) =12kΩ
12kΩ is parallel along 6kΩ resistor therefore
12k||6k = (12 x 6)/18
= 72/18 = 4kΩ
12kΩ is parallel along 4kΩ resistor therefore
12k||4k = (12 x4)/ (12+4)
= 48/16
= 3kΩ
Therefore through voltage division rule, the value of voltage across the corresponding 3kΩ resistor will be
V = (3/6) x12 = 6 V
Therefore the voltage across 3kΩ resistor will be
V = (3/12) x 6
=1.5 volts
The similar voltage shall be drop across 4kΩ resistor.