Diode Logic GAtes (OR Gate)

 Y=A+B+C

EXAMPLE 1: Determine V & I.

SOLUTION:

            D₁ is ON because this is in forward biased. Since 3V potential difference has been applied across diode D₁ and it shall go in more in conduction than D₂ & D₃.

                                                D₂ & D₃ are off.

                                    So,

                                                                        V= 3V

                                    Also by using Ohm's Law

                                                                          I = (3-0)/1k

                                                                          I = 3mA