Current Divider having Two Parallel Resistance Assignment Help

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Current Divider having two Parallel Resistances

It is frequently necessary to discover individual branch currents in any circuit however without knowing the value of branch voltage.

This difficulty can be solved by utilizing the fact that currents divide inversely like branch resistance. The formula is as

                                                    I1 = R2/R1 + R2 

Q:     Find the value of current through each resistance in given circuit

485_parallel resistance.png

Solution:

The current passing through 4 ohm Resistor shall be

                                                            I = 2/2+4 x 30

                                                              = 2/6 x 30 = 10A            

The current passing through 2 ohm resistor will be

                                                            I = 4 /2+4 x 30

                                                              = 4/6   x 30 = 20 A Ans. 

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