Newton's Third Law:
Every action is attended by an equivalent and reverse reaction. In another words, when an object A exerts a force vector F on an object B, then object B exerts a force vector - F (the negative of F) on object A.
PROBLEM:
The spacecraft of mass m = 10,500 (1.0500 x 104) kg in interplanetary space is acted on by a force vector of F = 100,000 (1.0000 x 105) N in the direction of Polaris, that is the North Star. Compute the magnitude and direction of the acceleration vector.
SOLUTION:
Use the primary formula stated former in Newton's second law. Plug up in the numbers for force magnitude F and mass m results the acceleration magnitude (a):
a = F/m
=1.0000 x 105/1.0500 x 104
= 9.5238 m/s2
The direction of the acceleration vector (a) is similar as the direction of the force vector F in this case, which is, toward the North Star. Since an interesting aside, you may notice that this acceleration is merely a little less than the acceleration of gravity at the Earth's surface that is 9.8 m /s2. And hence, a person inside this spacecraft would feel pretty at home; there would be an artificial gravitational field generated which would be just around the same strength as the gravity on Earth.