Problem of load sharing in the composite member:

Now, let us solve the problem of load sharing in the composite member illustrated in Figure 23. Here, we have

P = 60 kN

L = 400 mm

A₁ = (π/4) × 50² = 1963.5 mm²

A₂ = (π/4) × (90² - 50²) = 4398.23 mm²

A₃ =( π/4) × (120² - 90²) = 4948 mm²

Elastic moduli for the materials, as copper, aluminium and steel might be taken as 120 kN/mm² , 80 kN/mm², & 200 kN/mm² respectively.

 m₁ =   E₂ / E₁  =120/ 80 = 1.5

m₂ = E₃ / E₁ =200/ 80 = 2.5

Putting these values in Eq.),

= 5.6285 kN

Now, by using Eq. (10),

P₂ = (5.62852/ 1963.5) × 1.5 × 4398.23 = 18.912 kN

P₃ = (5.62852/ 1963.5 ) × 2.5 × 4948 = 35.4595 kN