Q:       Determine the value of the voltage Vo.

Solution:    We have to determine the voltage V₀.  The circuit may be redrawn like  

                        Here from the circuit

                                                I₂ = -4mA

                                                 I₃ =-1mA

            Now we can write

                                                 V_x = -(I₃ +I₄)1k

                                                             &

                                                      I₁ = 2V_x/1k

                                                 I₁ = -2(I₃ +I₄) = 2 - 2I₄          // I₃= -1mA

            Now by applying KVL for loop4

            -1k(I₄ +I₃) +1k(I₄ +I₃) +1k(I₄ +I₃ -I₂) +1k(I₄- I1) +2kI₄ = 0

                                                2kI₄ - 2 -1kI₄ +1 +1k (I₄ -2 +2I₄) +4 +2kI₄ += 0

                                                             6kI₄ +1 = 0

                                                                                6kI₄ = -1 = 1/6k

                        Now we can say

                                                             V₀ = 1k(I₄  + I₃)

                                                                   = 1k( -1/6 - 1)

                                                                                 = 1k(-.166 -1)

                                                              V₀= -1.166 V