Q. Calculate the value of current Io through the 3k ohm resistor in given circuit.         

Solution:

            For node A          (V₁/6k) + ((V₁ -V₂)/3k) =2mA            

                                                 Where V₂= 6Volts

Therefore by putting its value in the equation

((V₁ -6)/3k) + (V₁/6k) =2mA

             2V₁-12 + V₁ = 12

                            3V₁ = 24

                               V₁= 8 V ............(A)

By applying ohm's law

                        Io = (v₁-v₂)/3k

Put the value of V1 & V2 we get         

I₀ = (8 -6)/3k

     = 0.667 mA

  I₁ = 6/4k

      =1.5 mA