Velocity of Points in a Rigid Body Assignment Help

Assignment Help: >> Kinematics of a Rigid Body - Velocity of Points in a Rigid Body

Velocity of Points in a Rigid Body:

We consider the equation of pole A in the body as

rA (t ) = x A (t ) i¯ + y A (t ) j¯

 At any instant position vector of any other point B is provided by :

rB  = rA  + rAB

  507_Velocity of Points in a Rigid Body.pngis a vector of constant magnitude because distance AB is constant. But

the direction of this vector can change with respect to time so that d rAB/ d t does exist.

1619_rigid-body-translation.jpg

Then by differentiating, we obtain

vB = d rB/dt       = d rA/  dt + d rAB /dt

= v A  + d rAB/ d t

d rAB / d t  is the differentiation of a vector of constant magnitude but altering in direction. If ω is the angular velocity with which the body rotates about the axis, then we may write

                                                d rAB /dt = ω rAB

This is a vector v AB of magnitude ω. rAB , acting at right angles to AB.

Then                                v B = v A + v AB

Here, in this equation, we should note that velocity of B consists of two components.

(a)        The component v A which represents the velocity of translation of pole A.

 (b)       The component v AB of magnitude ω rAB  is caused by the rotation of point B about an axis passing through A, perpendicular to the plane XOY. This component shall be perpendicular to AB.

                                                           v B  = v A  + ω × rAB

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