Chelating Reaction Assignment Help

Assignment Help: >> Extraction of Metal Chelates - Chelating Reaction

Chelating Reaction:

The chelating anion, (R-), reacts with metal ion (Mn+) to form the chelate as shown below:

Mn+ + n R ↔ MR n

The creation constant of the complex Kf is provided as follows: [MRn] a

Kf = [MRn]a /[Mn+]a[R-]na

A metal chelate created on equilibration with the organic phase distributes itself between the aqueous and organic phases till equilibrium is attained.

(MRn)a  ↔      (MRn)o

The distribution constant of the complex, KDX, is given by

KDX =   [MRn]o  /[MR n ]a                                                                   (1)

We assume that the metal in the aqueous phase predominantly exists as Mn+ only and in the organic phase as MRn only. Alternatively, these assumptions could be elaborated as under:

i)          The metal ion forms no hydrolysis or anionic complexes in appreciable amounts.

ii)        The chelate concentration in the aqueous phase is negligible.

iii)       The concentration of the intermediate chelate species is negligible. If these assumptions are taken as valid, then

D = [M ]o /[M]a = [MR n ]o/[Mn+]a                                                (2)

By combining the Eqs. 3.1 Through Eq.2, the final Eq. 1 becomes as follows:

D= [MRn]o/[Mn+]a = KfKnaKDX/KnDR. [HR]no/[H+]na                                        

This equation has been experimentally verified for various metal chelate extraction systems. From the equation, it is evident that

D ∝ Kf, Kna , KDX and [HR]no

Also, D ∝ K - nDR and [H+] - na                                                                                         

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