Calculate the molar conductivity:
Problem:
The resistance of 0.1 M solution of a salt occupying a volume among two platinum electrodes 1.80 cm apart and 5.4 cm2 within area was found to be 32 ohms. Calculate the molar conductivity of the solution.
Answer:
Cell constant = l/A, 1.8/5.4 = 1/3 cm-1
Observed conductance = 1/32 ?-1
K = Cell constant × conductance=1/3 × 1/32 = 1/96 ?-1cm-1
Λm = K/c = 1/96 (?-1 cm-1) × 1/0.1 M
=1/96 (?-1 cm-1) × 1/0.1 × 10-3 (mole cm-3) =104.16 ?-1 cm2 mol-1