Calculate the conductivity of the experimental solution:

Problem:

A conductivity cell shows a resistance of 3950 ? at 25 ^oC when filled with the experimental solution and 4864 ? at the same temperature when filled with 0.02 M KCl solution. If the conductivity of the solution is 2.767 × 10^-3 S cm^-1, calculate the conductivity of the experimental solution.

Answer:

Cell constant = KR = 2.767 × 10^-3 (S cm^-1 ) × 4864 (?) Conductivity of the experimental solution = K= Cell constant/R

=   2.767 × 10^-3 × 4864 (cm^-1)/3950(?) = 3.407 × 10^-3 S cm^-1