Compute the grams of product:
Problem:
A constant current of 2 A was passed for 6 min. containing CuSO4 solution.
Compute the grams of each product that was formed on each electrode assuming no other redox reactions.
Answer:
The quantity of current, Q=I×t=2×6×60=720 C
At cathode Cu2+ +2e → Cu
Therefore, 1 mol of copper is equivalent to 2 mol of electrons. According to
Faraday's law nA = Q/nF
nCu = 3.731×10-3 mol Cu
Mass of Cu = 63.5 × 3.731×10-3 =0.2369 g.