Faradays Second law of electrolysis Assignment Help

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Faraday's Second law of electrolysis:

The mass of variant substances evolved/deposited through the passage of similar quantity of electricity are proportional to their chemical equivalence.

m  ∝  Mr/n = Equivalent weight of substance

whereas m is the mass of the substance liberated or deposited, Mr is the molar mass of the substance liberated/deposited and n is the valency number of ions of the substance (electrons transferred per ion).

If m1 and m2 are the mass of two variant substances liberated through the passage of similar amount of electricity and M1 and M2   are their respective molar masses and n1 and n2 are their respective valence number of ions, then

m1n1/M1 = m2n2/M2

For instance, let us consider the passage of electricity by solutions of CuSO4 and AgNO3 linked in series, so in which the similar amount of electricity is passed by them, then from the second law, we get

Mass of copper deposited × 2/ Molar mass of copper = Mass of silver deposited ×1/Molar mass of silver

The quantity of electricity or charge (Q) is equivalent to the product of current strength or charge and time for that the current is passed.

Q = current × time = I × t

The practical unit of electricity is coulomb.

where a current of 2 ampere flows for ten seconds and a quantity of electricity (Q) in coulombs is, current in amperes (I) multiplied through the time in seconds (t).

Q = ampere (I) × seconds (t) = 2 × 10 = 20 C.

For a variable current I, the electricity

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