Lag Lead Correlation Assignment Help

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Lag Lead Correlation

The study of lag and leads has its special significance while studying the economics and business series. In the correlation of time series the investigator may find that there is a time gap before a cause and an effect relationship is established. For e.g.  The supply of a commodity may increase nowadays, but it may not have an immediate effect on prices- it may take a few days or even months for prices to adjust to the increased supply. This difference in the period before a cues and effect relationship is established is called while computing the correlation. Their gap in time must be considered otherwise fallacious conclusions may be drawn. The pairing of items is adjusted according to the time lag.

Taking the new pairs of values, the correlation can be calculating in the same manner as discussed earlier:

Illustration:

The following are the monthly figures of advertising expenditure ad sales of a firm. It is normally found that the advertising expenditure has its impact on sales normally after 2 months. Allowing for this time the lag calculates coefficient of correlation.

Months

Advertising expenditure

Sales

Months

Advertising

Sales

Jan

50

1200

July

140

2400

Feb

60

1500

Aug

160

2600

March

70

1600

Sep

170

2800

April

90

2000

Oct

190

2900

May

120

2200

Nov.

200

3100

June

150

2500

Dec.

250

3900

Solution:

Allow for a time lager of 2 months link advertising the expenditure of January with sales for March and so on.

Calculation of correlation coefficient:

month

Advertising expenditure X

(X - X) / 10X

X2

Sales Y

(Y-Y) / 100 y

Y2

xy

Jan

50

-7

49

1600

-10

10

70

Feb.

60

-6

36

2000

-6

36

36

March

70

-5

25

2200

-4

16

20

April

90

-3

9

2500

-1

1

3

May

120

0

0

2400

-2

4

0

June

150

+3

9

2600

0

0

0

July

140

+2

4

2800

+2

4

4

Aug.

160

+4

16

2900

+3

9

12

Sep

170

+5

25

3100

+5

25

25

Oct.

190

+7

49

3900

+13

169

91

 

ΣX = 1,200

ΣX= 0

Σx2 = 222

Σy =26,000

Σy =0

Σy2=364

Σxy = 261

R = Σ Xy /Σx2 x Σy2

X = 1.200 / 10 = 120

Y = 26,000/10=2,600

Σxy = 261 Σx2 = 222, Σy2 = 364

R = 261/222x 364 = 261/284.267 = + 0.918.

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