Q: Find out the output voltage for the network indicated in the diagram.
SOLUTION: Diode shall be on for the negative half cycle .therefore the effective circuit is shown in the diagram.
By apply Id = 0, Vd =0 to obtain transition voltage so that
Vi - IdR - 4V =0
Vi - 0R - 4V =0
Vi = 4V is transition voltage.
Therefore for the positive half cycle
VL = V0
VL = 16 V.