Addition of a Battery in the Series Clipper Circuit

• In the diagram. The direction of the diode recommends that the signal V_i have to be positive to turn on it. Further the dc supply needs that the voltage V_i be

higher than V volts to turn on the diode. The negative region of input signal is pressuring the diode into off region.

• Now we find out the applied voltage which will cause a modifying in state for the diode. The ideal diode transition take place  at the point on the characteristic here V_d= 0 & I_d = 0

• In this matter transition will take place at

                                                            V_i = V                           

While the diode is short circuited as indicated in the diagram. The output voltage V₀ may  be determined  by applying KVL equation

                                                V_i - V  - V₀ = 0

                                                            V₀  = V_i - V

• In this matter

                                                V₀  = V_m  - V