Q. Find out v₀ for the network shown in the diagram.

SOLUTION:

Our analysis shall start at time t₁ to t₂ .our circuit shall behave as indicated in the diagram. By applying KVL to input loop

                                                -20 + V_c - 5 = 0

                                                     V_c = 25V

The capacitor shall consequently charge up to 25V. In this the resistor shall not be shorted by the diode, however a Thevenin's correspondent circuit for that part of the network which includes the battery & resistor shall result in R_th = 0, with    E_th = V = 5V. 

            For the period t₂ to t₃ the circuit is indicated in the diagram.

By applying KVL across the outer loop

                                                            10 + 25 - V_o = 0

                                                                           &

                                                            V_o = 35V

The time constant of the discharging network of diagram is find out by the product of R_C and contain magnitude

                                                 T = R_C = 0.01S

            The output wave form shall obtain the shape like