Q. For the circuit given determine R_E & R_C.

Solution:

The known parameters are

                                                                I_c=0.5mA & α=1,

                                                                                V_CB=2V

                                                Thus, for the output loop we have through KVL

                                                                                (10-6)/0.5m=R_C

                                                                                                R_C=2kΩ

                                    α=1,

                                Thus,

                                                                                I_C=I_E=0.5mA

                                                Therefore for the base emitter loop by KVL

                                                                                (4-0.7)/0.5m=R_E

                                                                                              R_E=2.6k Ω