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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
Solution) Y=θ[SIN(INθ)+COS(INθ)]applying u.v rulethen dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SIN(INθ)+COS(INθ) + θ{ (COS(INθ)÷ θ) - (SIN(INθ)÷θ) } θ is canceled and sin(ln θ ) is also canceled then u will get => 2COS(INθ)
Trace the curve (x/a)^3/2+(y/b)^2/3=1
Tom has five times as many marbles as Jim. together they have 42 marbles. how many marbles does each has?
Volumes of Solids of Revolution / Method of Cylinders In the previous section we started looking at determine volumes of solids of revolution. In this section we took cross se
Chi-square hypothesis tests as Non-parametric test(X2) They contain amongst others i. Test for goodness of fit ii. Test for independence of attributes iii. Test
#pqrs is a parallelogram its adjacent side is 2:1.state tHE angles
MAXIMAX method Maximax method is based upon 'extreme optimism' the decision maker chooses that particular strategy which corresponds to the maximum of the maximum pay off for e
how do i solve reflection matrix just looking at the numbers in a matrix
If α, β are the zeros of the polynomial x 2 +8x +6 frame a Quadratic polynomial whose zeros are a) 1/α and 1/β b) 1+ β/α , 1+ α/β. Ans. P(x) = x 2 +8x +6 α + β = -8
how many sides does a regular hexagon have?
The probability that a leap year will have 53 sunday is ? and how please explain it ? (a)1/7 (b) 2/7 (c) 5/7 (d)6/7 Sol) A leap year has 366 days, therefore 52 weeks i.e
y=Θ[sin(lnΘ)+cos(lnΘ)] dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule) dy/dΘ=2cosΘ.
y=Θ[sin(lnΘ)+cos(lnΘ)]
dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)
dy/dΘ=2cosΘ.
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