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Explain the role that XML can play when dynamically generating HTML pages from a relational database?
Ans) Even if student has never participated in a project involving this type of architecture, they should identify it as one of the common uses of XML. Querying a database and then formatting the result set so that it can be validated as an XML document permits developers to translate the data into an HTML table using XSLT rules. Thus, the format of the resulting HTML table can be modified without changing the database query or application code as the document rendering logic is isolated to the XSLT rules.
You insert rendezvous points into Vuser scripts to imitate heavy user load on the server. Rendezvous points instruct Vusers to wait during test implementation for multiple Vusers t
What are the advantages of using XML over HTML? The root cause of the problem lies in HTML (Hyper Text Mark-up Language), the defacto standard for web publication. The main pr
Explain path testing. Path Testing: Testing in which all paths in the program source code are tested at least once. Path testing has been one of the first test methods, and e
The method(s) of payment for online consumers are A) Electronic cash (B) Credit/debit C) Electronic checks
Define the Half Duplex Transmission A half-duplex channel can receive andsend, but not at the same time. It's like a one-lane bridge where two-way traffic should give way in
Program Level : It is the next level consisting of independent programs for parallelism. Coarse Granularity size is used at this level containing ten thousands of instructions.
Design a BCD to excess 3 code converter using minimum number of NAND gates. Hint: use k map techniques. Ans. Firstly we make the truth table: BCD no
What is Read only memory (ROM) and Define the Use of it? A simple kind of ROM can be constructed from a decoder, Or gates, and a number of wires. Input
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Simplify the given expressions using Boolean postulates Y = (A + B)(A‾ + C)(B + C) Ans. Y = (A + B)(A‾ + C)(B + C) = (A A‾ + AC + B A‾ + BC) (B + C) = (AC + B A‾ + BC) (B + C)
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