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Write Policy
A write policy determines how the cache deals with a write cycle. The 2 common write policies areWrite-Throughand Write-Back. In Write-Back policy, the cache behave like a buffer. That is, when the processor begins a write cycle the cache receives the data and end the cycle. The cache then writes the data back to main memory when the system bus is available. This method provides the higher performance by let the processor to continue its job when main memory is updated at a later time. However, controlling writes of themain memory increase the cache's complexity and price. The second method is the Write-Through policy. The processor writes through the cache to main memory. The cache can update its contents, however the write cycle does not end till the data is stored into main memory. This method is less complicated and therefore less expensive to implement. The efficiency with a Write-Through policy is lower since the processor might wait for main memory to accept the data.
relocation
Zero flag: The next line compares the value in register. A with the value 1. If they are equivalent, the Zero flag is set (to 1). The next line then jumps to start: only if th
DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in t
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H
how to find out the given number is positive or negative?
A good starting point for your program is the toupper.asm program shown in class. It already queries the user for input and sets up a loop that looks at each character of the input
init_lcd ;(this initialises a 2 row lcd) bcf TRISA,0 ;PORTA bit 0 as an output (lcd RS pin) bcf TRISA,1 ;PORTA bit 1
The main objective of the assignment is to explore the knowledge regarding parallel ports of a computer system. You can read and write datato/from the parallel port using IN and OU
DAA: Decimal Adjust Accumulator:- This instruction is utilized to convert the result of the addition operation of 2 packed BCD numbers to a valid BCD number. The conclusion has to
You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2
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