Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Write notes on clamping ?
Clamping network shifts (clamps) a signal to a different d.c level, that is it introduces a d.c. level to an a.c signal. Hence, the clamping network is also known as d.c reference signal to the video signal. The clamping network has the various circuit components like a diode, a capacitor and a resistor. The time constant for the circuit G=RC must be large so that the voltage across the capacitor does not discharge significantly when the diode is not conducting.
In the clamper circuit the diodes are assumed to be ideal. A square waveform with maximum amplitude of V is given as the input to the network. During the positive half cycle, the diode conducts, ie it acts like a short circuit. The capacitor charges to V volts. During this interval, the output which is taken across the short circuit will be V0= 0 V. During the negative half cycle, the diode is open. The output voltage can be found out by applying Kirchoff's Law.
-V-V-V0 = 0
Therefore, V0= -2V
The analysis of the clamper circuit can be done as follows. Determine the portion of the input signal that forward biases the diode. When the diode is in short circuit condition, the capacitor charges up to a level determined by the voltage across the capacitor in its equivalent open circuit state. During the open circuit condition of the diode, it is assumed that the capacitor will hold on to all its charge and therefore voltage. In the clamper networks, the total swing of the output is equal to the total swing of the input signal.
Explain the terms: valence band, conduction band, valence electrons, and energy gap with the help of suitable diagrams. Valence Electrons: The electrons in the outermost orbi
Q Determine the effective input noise temperature of a long piece of waveguide (that connects an antenna to a receiver) with a loss of 3.4 dB at 12 GHz and a physical temperature o
Q. In the non inverting summing amplifier of Figure, let R d = 1k and M = 6. Find R f so that v =
Determine currents in the circuits: Determine currents I 1 and I 2 in the given circuits by applying KVL. Solution We apply KVL for first loop : 10 = 1 I 1 + 1
Q. Afixed-biasmethod is illustrated in Figure. Assuming ICBO to be small compared to I BQ and I CQ , find RB such that the operating point corresponds to I CQ = 14 mA, V CEQ = 7
circuit diagram,working and construction of voltmeter
Followings are the Disadvantages of PLC a.Too much work required in connecting wires. b.Difficulty with changes or replacements. c.Difficulty in finding errors requi
Aims More practice using data movement and control flow statements. Understand techniques to interface microprocessors with external switch-based hardware. Write P
GIS application architecture: GIS application architecture should 1 Give a framework and the essential programming interfaces to enable complex GIS applications to be deve
Q. Explain Time-Dependent Circuit Analysis? The response of networks to time-varying sources is considered in this chapter. The special case of sinusoidal signals is of particu
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd