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Two linked lists are having information of the same type in ascending order. Write down a module to merge them to a single linked list that is sorted
merge(struct node *p, struct node *q, struct **s)
{
struct node *z;
z = NULL;
if((x= =NULL) && (y = =NULL))
return;
while(x!=NULL && y!=NULL)
if(*s= =NULL)
*s=(struct link *)malloc(sizeof(struct node *z));
z=*s;
}
else
z-->link=(struct link *)malloc(sizeof(struct node *));
z=z-->link;
if(x-->data < y-->data)
z-->data=x-->data;
x=x-->link;
else if(x-->exp > y-->exp)
z-->data=y-->data;
y=y-->link;
else if(x-->data= =y-->data)
while(x!=NULL)
z link = struct link *malloc(sizeof(struct node *));
z=z link;
while(y!=NULL)
z-->link=NULL;
Here, m represents the unordered array of elements n represents number of elements in the array and el represents the value to be searched in the list Sep 1: [Initialize]
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Link list representation of a circular queue is more efficient as it employs space more competently, of course with the added cost of storing the pointers. Program 7 gives the link
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In the array implementation of lists, elements are stored into continuous locations. In order to add an element into the list at the end, we can insert it without any problem. But,
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