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Two linked lists are having information of the same type in ascending order. Write down a module to merge them to a single linked list that is sorted
merge(struct node *p, struct node *q, struct **s)
{
struct node *z;
z = NULL;
if((x= =NULL) && (y = =NULL))
return;
while(x!=NULL && y!=NULL)
if(*s= =NULL)
*s=(struct link *)malloc(sizeof(struct node *z));
z=*s;
}
else
z-->link=(struct link *)malloc(sizeof(struct node *));
z=z-->link;
if(x-->data < y-->data)
z-->data=x-->data;
x=x-->link;
else if(x-->exp > y-->exp)
z-->data=y-->data;
y=y-->link;
else if(x-->data= =y-->data)
while(x!=NULL)
z link = struct link *malloc(sizeof(struct node *));
z=z link;
while(y!=NULL)
z-->link=NULL;
For preorder traversal, in the worst case, the stack will rise to size n/2, where n refer to number of nodes in the tree. Another method of traversing binary tree non-recursively t
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