Write an assembly language program, Assembly Language

Assignment Help:

You are to write an assembly language program called subfaq.s that computes the generalized subfactorial function of nonnegative integer inputs i0 and n. The generalized subfactorial function is defined by the following recursion.

gs(0) = 1
inc(0) = i0

gs(n) = n gs(n-1) - inc(n-1)
inc(n) = -inc(n-1)

The generalized subfactorial function is closely related to the factorial function:
Factorial(n) can be written n! and is equal to gs(n) when i0 = 0.
Subfactorial(n) can be written !n and is equal to gs(n) when i0 = 1.

The values of both factorial and subfactorial get large very rapidly as n increases, so your program should return a 64-bit number representing gs(n) mod 264. In other words, just let your 64-bit register overflow. Try to make your code as short and efficient as possible. I recommend not using recursion, but rather writing a loop that starts from 0 and increments up to n. Write your assembly code from scratch rather than writing C and compiling to assembly. It takes only 10 to 20 instructions, and this will be your only assignment to write code in assembly. Don't miss out on the experience. You may copy your procedure entry and exit code from the textbook or the gcc compiler output without citing the source. Try to get your assembly code for subfac.s to occupy at most 50 bytes (30 is possible). To see your machine code, use
gcc64 -c subfaq.s

to produce object file subfaq.o , then use
objdump64 -d subfaq.o .

The following C program (called run_subfaq.c ) can be used to test your subfaq function. Do not include it with your submission; I already have it.

lli subfaq(int n, lli i0);

int main(int argc, char* argv[])
{
int i = 1, n;
lli i0, ans;
if(argc < 3) {printf("Usage: gs i0 n1 n2 n3 ... (list of non-negative integers)"); return -1;}
sscanf(argv[i++], "%lld", &i0);
while (i < argc) {
sscanf(argv[i], "%d", &n);
if(n < 0) printf("%d out of range\n", n);
else {
ans = subfaq(n, i0);
printf("gs(%d, %lld) = %lld\n", n, i0, ans);
}
i++;
}
return(0);
}

The compile command to test your programs will look like this:
gcc64 -Wall -std=gnu99 -o gs run_subfaq.c subfaq.s .
Here are two sample outputs to use in testing your programs.
C:>gs 0 0 1 2 3 4 5 6 13
gs(0, 0) = 1
gs(1, 0) = 1
gs(2, 0) = 2
gs(3, 0) = 6
gs(4, 0) = 24
gs(5, 0) = 120
gs(6, 0) = 720
gs(20, 0) = 2432902008176640000
gs(21, 0) = -4249290049419214848
gs(
C:>gs 1 0 1 2 3 4 5 6 13
gs(0, 1) = 1
gs(1, 1) = 0
gs(2, 1) = 1
gs(3, 1) = 2
gs(4, 1) = 9
gs(5, 1) = 44
gs(6, 1) = 265
gs(20, 1) = 895014631192902121
gs(21, 1) = 348563181341392924

(The outputs for n = 21 have overflowed the 64-bit word size.)


Related Discussions:- Write an assembly language program

Opcode-microprocessor, Opcode : The opcode generally appear in the firs...

Opcode : The opcode generally appear in the first byte.but in a few instructions, a register objective is in the first byte and few other instructions may have their 3-bits of

Interrupt system based on 8259 a-microprocessor, Interrupt System Based on ...

Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage.  Its organization is shown in given figur

2 homework assignements, I have two homework assignments due in 10 hours fo...

I have two homework assignments due in 10 hours for the x86 processor assembly language

Minecraft/Terminal issues, I am running a small minecraft server off of my ...

I am running a small minecraft server off of my old mac mini, and am having a big issue. My computer isn''t very good, and even just running this server is an issue. I use a comma

8088 associated with 8259 a-microprocessor, For an 8088 the 2 addresses lin...

For an 8088 the 2 addresses linked with an 8259A are normally consecutive, and the AO line is associated to the AO pin, but because there are just 8 data pins on the 8259A and the

How to write an assembly program-microprocessor, How to write an assembly p...

How to write an assembly program The initial step in writing an assembly language program is to identify and study the problem. After studying the problem, choose the logical m

Into-jmp-unconditional branch instruction-microprocessor, INTO : Interrupt...

INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT

Al registre, check the al-register for palindromic number

check the al-register for palindromic number

8086, to separate positive and negative numbers

to separate positive and negative numbers

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd