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Post-order Traversal : This can be done by both iteratively and recursively. The iterative solution would require a modification or alteration of the in-order traversal algorithm.
Refer: https://www.expertsmind.com/questions/in-order-traversal-3016324.aspx
https://www.expertsmind.com/questions/algorithm-for-pre-order-traversal-3016323.aspx
N = number of rows of the graph D[i[j] = C[i][j] For k from 1 to n Do for i = 1 to n Do for j = 1 to n D[i[j]= minimum( d ij (k-1) ,d ik (k-1) +d kj (k-1)
for i=1 to n if a[i}>7 for j=2 to n a[j]=a{j}+j for n=2 to n a[k]=a[j]+i else if a[1]>4 && a[1] for 2 to a[1] a[j]= a{j]+5 else for 2to n a[j]=a[j]+i ..
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