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Write a Prolog predicate has_duplicates(L) that is true if list L contains duplicated elements (that is at least 2 copies of an element). For instance:
?- has_duplicates([a,e,b,d,s,e]).
Yes
?- has_duplicates([a,b,d,s,e]).
No
?- has_duplicates([]).
(a) Define a procedure (subsets x) that takes a list as a single argument and returns all 2^n subsets of that list, i.e. the power set of the list; e.g. (subsets '(a b c)) ==> (
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