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Write a Prolog predicate remove_nth(N,L1,L2) that is true if list L2 is just list L1 with its Nth element removed. If L1 does not have an Nth element then the predicate should fail. You can assume that N is strictly greater than 0. For instance:
?- remove_nth(4,[a,e,e,d,s,e],L).
L = [a,e,e,s,e] ;
No
?- remove_nth(6,[a,b],L).
Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4
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