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Write a Prolog predicate remove_nth(N,L1,L2) that is true if list L2 is just list L1 with its Nth element removed. If L1 does not have an Nth element then the predicate should fail. You can assume that N is strictly greater than 0. For instance:
?- remove_nth(4,[a,e,e,d,s,e],L).
L = [a,e,e,s,e] ;
No
?- remove_nth(6,[a,b],L).
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I have doubt in this section .do-while loop.could you able to clear it for me.
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