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Write a Prolog predicate remove_nth(N,L1,L2) that is true if list L2 is just list L1 with its Nth element removed. If L1 does not have an Nth element then the predicate should fail. You can assume that N is strictly greater than 0. For instance:
?- remove_nth(4,[a,e,e,d,s,e],L).
L = [a,e,e,s,e] ;
No
?- remove_nth(6,[a,b],L).
write a class
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Write a Prolog predicate has_duplicates(L) that is true if list L contains duplicated elements (that is at least 2 copies of an element). For instance: ?- has_duplicates([a,e,b,
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