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Write a Prolog predicate remove_nth(N,L1,L2) that is true if list L2 is just list L1 with its Nth element removed. If L1 does not have an Nth element then the predicate should fail. You can assume that N is strictly greater than 0. For instance:
?- remove_nth(4,[a,e,e,d,s,e],L).
L = [a,e,e,s,e] ;
No
?- remove_nth(6,[a,b],L).
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A function that takes a list with at least 4 numbers and if three of the numbers sum is equal to the remaining numbers return #t else return #f
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