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The Cigarette-Smokers difficulty Consider a system with three smoker processes and one agent process. Every smoker continuously rolls a cigarette and then smokes it. But to roll as well as smoke a cigarette the smoker needs three ingredients: paper, tobacco and matches. One of the smoker progression has paper another has tobacco and the third has matches. The agent has an endless supply of all three materials. The agent put two of the ingredients on the table. The smoker who has the residual ingredient then makes and smokes a cigarette signalling the agent on completion. The agent then places out another two of the three ingredients and the cycle repeats. Write a program to synchronize the agent as well as the smokers using Java synchronization.
Q. Most WANs utilize only a partially connected topology. Why is this subsequently Answer: Cost. A completely connected network requires a link between every node in the netw
Explain external fragmentation? External fragmentation is the process where the free space and the space still available for use, in a piece of storage become separated into ma
Define deadlock prevention. Deadlock prevention is a set of process for ensuring that at least one of the four essential conditions like mutual exclusion, hold and wait, no pr
Linked list allocation: At this time the blocks are stored using linked lists. The block size require not be the same. Thus internal fragmentation is avoided. Consider
Fault tolerance Machine failures, Communication faults, storage device crashes, and decays of storage media should be tolerated by the system to some extent. A fault tolerant s
Literature review
What do you mean by system calls? System calls give the interface among a process and the operating system. When a system call is implemented, it is treated as by the hardware
What is graceful degradation? In multiprocessor systems, failure of single processor will not halt the system, but only slow it down by sharing the work of failure system by ot
Ok so i think i got this right by not 100% on this. what I want to figure out is if there are x visitors that can line up for a ride but only 1 passenger can get on the ride at a t
mention the three problems that mat be caused by wrong initialization and placement of wait() and signal()operations in the use of semaphore
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