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The Cigarette-Smokers difficulty Consider a system with three smoker processes and one agent process. Every smoker continuously rolls a cigarette and then smokes it. But to roll as well as smoke a cigarette the smoker needs three ingredients: paper, tobacco and matches. One of the smoker progression has paper another has tobacco and the third has matches. The agent has an endless supply of all three materials. The agent put two of the ingredients on the table. The smoker who has the residual ingredient then makes and smokes a cigarette signalling the agent on completion. The agent then places out another two of the three ingredients and the cycle repeats. Write a program to synchronize the agent as well as the smokers using Java synchronization.
Define Instance. An instance is an administrative unit in which components of R/3 systems giving one or more services are grouped together. The services offered by a case are
What OS''s are available in market as open source?
What is a multiprocessing system? Multiprocessor systems are those systems that use additional than a single processor for program execution. It is done for raising the executi
Why are segmentation and paging sometimes combined into one scheme? Segmentation and paging are often combined in order to improve upon each other. Segmented paging is helpful
Ask question #Minimum 100 words accepted application of bounded and unbounded buffers
Difference between threads and processes 1. Thread is flow of implementation. Process is group of instruction which is alike to that of a program except which may be stopped an
Q. Consider a distributed system with two sites A and B. Consider whether site A can distinguish among the following: a. B goes down. b. The link between A and B goes down.
Q. List the four steps that are essential to run a program on a completely dedicated machine. Answer: a) Reserve machine time b) Manually load program into memory c)
What is bounded buffer
There is a process bloacked by a semaphore and no other process in the ready queue, can the blocked process get back to the ready queue without the semsignal() function?
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