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Write a Program to illustrate the call by value?
#include . int compute_sum(int m); int main( void) { int n=3, sum; printf("%d\n",n); /*3 is printed */sum=compute_sum(n);printf("%d\n",n); /*3 is printed */ printf("%d\n",sum); /*6 is printed */ return 0; }
int compute_sum(int n) /*sum the integers from 1 to n*/ 9 { int sum=0; for (;n>O;--n) /*stored value of n is changed*/ sum+=n; return sum; }
Even although n is passed to compute_sum() and the value of n in the body of that function is changed the value of n in the calling environment remains unchanged It is the value of n that is being passed, not n itself.
Write out the Syntax of Nested if Statements? The universal form is If(expression 1) {
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Write a function called triple (in a file called 'triple.m'). That takes a single variable x and returns a single variable in which every element of x is multiplied by 3. Make sure
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wat is- m=5; n=3; x=m++-n+++m;
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