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The formula for resistors linked in parallel is a little more complex. Given two resistors along with resistances R1 and R2 linked in parallel the equivalent resistance is given through the inverse of the sum of the inverses, i.e.
1 Requiv = -------- 1 1 -- + -- R1 R2If there are more than two resistors you continue to invert the sum of their inverses; e.g. for four resistors you have: 1Requiv = ------------------ 1 1 1 1 -- + -- + -- + -- R1 R2 R3 R4
Write a program that calculates the resistance of a a group of resistors arranged in parallel. The resistances will all be passed as command line arguments.
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What is best algorithm? Greedy algorithm is the best algorithm as it is n algorithm in which always takes the best immediate, or local solution although searching an answer.
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