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Q. Write a note on the application of emitter-follower?
An emitter follower can serve as a buffer for a voltage source. The voltage divider at left is a poor voltage source because it is so strongly affected by the value of the load resistor. The same voltage divider with the transistor buffer at right will supply power to keep the voltage constant over its range of operation.
The simple voltage divider will give a 4V output for an open circuit, but quickly drops when larger loads (smaller load resistors) are connected. The buffer helps to keep the output voltage more nearly constant. You can change the value of the load resistor below to explore the effect of the buffer.
Q. Illustrate the Simplex Transmission? Simplex Transmission Data in a simplex channel is always one way. Simplex channels aren't often used as it is not possible to send ba
Compare with Register The contents of the register are compared with the contents of the accumulator here register may be any one of the A, B, C, D E, H, or L reg
#Explain charging and discharging of the capacitor ..
Q. What do you mean by Pinch off voltage? As the voltage Vds is increased from 0 to a few volts, the drain current will increase as determined by Ohm's law and the plot of Id
Q. A JK flip-flop is shown in Figure (a). (a) Modify it to operate like the D flip-flop of Figure (b). (b) Modify the JK flip-flop to operate like the T flip-flop of Figure (
Revenue Loss Due to Loss of Opportunity to Serve The revenue loss because of "loss of opportunity to serve" is a extremely relevant but less visible aspect of revenue loss. Gu
sketching of wire 1 is charged and wire 2 uncharged
Explain Hand shakingfor the allocation of addresses to memories and input output devices. Hand shaking: During an ASYNCHRONOUS data transfer is not based upon predetermined tim
First section Aim: the aim of this project is to produce a storage scope using a PIC. In this project, several samples were taken from an analog signal and stored in the memo
Q. Show Maximum Differential Input Voltage of amplifier? This is the maximum value of differential input voltage v p - v n that can be applied without damaging the op amp.
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