Write a assembly language subroutine, Assembly Language

Assignment Help:

Write a M68000 assembly language subroutine MULSUM that takes an array named A containing n bytes of positive numbers, and fills two arrays, array B containing n words and array C containing n long words as follows:

Sum = 0;

for(i = 0; i)
Sum = A[i] + Sum;
if(Sum is an EVEN number) then

B[i] = Sum;
 else
C[i] = Sum * A[i];
 end if
end for

In evaluating the expression Sum * A[i] you are NOT allowed to use the MULTU, or MULTS instructions, hence, you are to find another way to calculate this expression.

Main program along with data section is shown below. This program passes all the required parameters to subroutine MULSUM by pushing them on stack.

Note: There is no overflow occurring during any operation.

a) Write the main program

b) Write the subroutine MULSUM

c) Show the stack frame for entire program and clearly label SP at different stages of program.


Related Discussions:- Write a assembly language subroutine

Counters, #question. counters using 8051.

#question. counters using 8051.

Instruction set of 8086-microprocessor, Instruction set of 8086 : The 8...

Instruction set of 8086 : The 8086/8088 instructions are categorized into the following major types. This section describes the function of each of the instructions with approp

Type of microprocessor , Type of Microprocessor : Microprocessors fal...

Type of Microprocessor : Microprocessors fall into 3 categories: Single Chip Microcomputers: - Contains RWM, ROM, microprocessor, I/O port, timer and clock. General pu

#title, how i can write a program to divide 2 numbers

how i can write a program to divide 2 numbers

PIC, LIST p=18f4550 #include org 0x0000 movlw 0x00 _________ movlw 0xFF ...

LIST p=18f4550 #include org 0x0000 movlw 0x00 _________ movlw 0xFF movwf PORTB end .

Segmentation, segmentation and overlapping in assemble language

segmentation and overlapping in assemble language

Display control-microprocessor, Display control 8279  provides  a  16  ...

Display control 8279  provides  a  16  byte  display  memory  and  refresh  logic.  Every address in the display memory corresponds to a display unit with address zero represen

Call-unconditional branch instruction-microprocessor, CALL : Unconditional...

CALL : Unconditional Call:- This instruction is utilized to call a subroutine from a basic program. In case of assembly language programming, the term procedure is utilized int

Sub-arithmetic instruction-microprocessor, SUB: Subtract :- The subtract in...

SUB: Subtract :- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory locati

Can you write this Program for me please? , $NOMOD51 $NOSYMBOLS ;**********...

$NOMOD51 $NOSYMBOLS ;***************************************************************************** ; Spring 2013 Project ; ; FILE NAME : Project.ASM ; DATE : 3/30/20

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd