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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
fms computer control system
Find out the velocity of the system: Blocks A and B of mass 20 kg and 45 kg, respectively are associated by a weightless rope over a frictionless pulley as shown in Figure a).
write short note on''coefficient of insensitiveness''of governors.
Edge joints: The flanged edge joint is suit- able for plate 1/4 inch or less in thickness and can only sustain light loads. Edge preparation for this joint may be done.
how to do work in cam and follower?anser in hindi type
degrees of freedom of a planar mechanism
Repair of surface defects in welds by chipping, grinding and gouging is permitted provided the thickness is not reduced below the minimum required. Removal of defects shall be ver
Q - Derive bending equation that is,; M / I = σ / y = E / R . Sol.: With reference t
Alternating Current ( AC ) : The electricity whose direction changes at regular interval is known as alternating current. I
Calculate tension in limbs: Q : A horizontal drum of belt drive carries the belt over semicircle around it. It is rotated counter clockwise to transmit a torque of 300N-m. If
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