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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
#applications radius of curvature..
Q. Procedure for calculating the wind force on vessels? The National Building Code of Canada has a similar procedure for calculating the wind force on vessels as ASCE. The bas
offset method to draw parabola
A lifting shackle in a glass-making factory is made from a special high-temperature stainless steel. It is expected that the shackle will experience a tensile load of 5kN and th
Implementation of Material Requirement Planning: The total requirements for a material from an MRP schedule are given in the following table :
Three forces act on particle: Thr ee forces act on particle ' O ' as shown in the figure given below. Determine the value of ' P ' such that resultant of these three forces
optmization
Split the harmonic motion x=10 sin (wt + 30 0 ) into two harmonic motions one having a phase angle of zero and the other of 45 0 . Describe and derive an expression for energy m
Definition of stepped pulley
How is works watery flayer?
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