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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
Equilibrium in concurrent force system: Sol.: The steps for solving problems of equilibrium in concurrent force system are as follows: 1. First draw free body diagram
Rubber Hoses: Fuel or vacuum hoses should be installed so that end is bottomed into its fitting which would ensure adequate area for the hose clip to grip the hose beneath the fla
Hazardous Areas are formally ranked as being a designated hazardous area using the relevant regional or country standards that are directly applicable to the plant design under con
what is the different torque rating of a helical gear one direction verses the other
torque
(a) Split up the harmonic x = 8 sin(ωt + 45°), into two harmonic motions, one of which has amplitude of 10 and phase difference zero. (a) A body is subjected to two harmonic mot
Draw bending moment diagram: Draw the shear force diagram (SFD) & bending moment diagram (BMD) for the beam illustrated in Figure . Solution Reaction at the support A,
What is Tube Drawing - cold drawing processes This kind of drawing is very similar to bar drawing process and in majority of cases it is accomplished by the use of a draw be
Find length of belt: Find length of belt which is required to drive a pulley of 500mm diameter running parallel at the distance of 12m from driving pulley of diameter 1600m.
How can punching shear failure are characterised in bearing capacity? Punching Shear Failure This mode of failure is characterised by large deformations beneath the footing
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