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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
A tensile test on a specimen having an initial diameter of 13.11 mm and an initial gauge length of 200.0 mm, gave the following data:
briefly explain
Determine least value of work: Q . Determine least value of W as shown in the figure given below to keep the system of connected bodies in equilibrium µ for surface of c
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COMPETENCY STATEMENT: In this programme, every learner shall be assessed on a continuous basis for his/her knowledge and skills during the programme duration. Learners' competenc
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