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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
Principle of equilibrium: Sol.: Principle of equilibrium can be divided in to three main parts; (1) Two Force Principle: As the Resultant is zero when body is in equili
Plot Plan Alignment Generally the process units will be positioned in process flow order, with common utility blocks positioned to provide economical and effective services. P
Understanding the Role of Ownership : Before starting a business, entrepreneur should know what is involved in owning a business and what are the roles one will have to play to st
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V elocit y Ratio for Open Belt Drive: Figure Consider a simple belt drive (that is one driver and one follower) as shown in the figure given below Let D 1
Ott o Cycle (1876): This cycle consists of the two reversible adiabatic processes and the two constant volume processes as shown in the figure given below on P - V and T -
how thw trippaning process work
A sign of uniform density weighs 270 lb and is supported by a ball-andsocket joint at A and by two cables. Determine the tension in each cable and the reaction at A.
can a swimming pool that is full be cracked or lifted by hydrostatic pressure?
Procedure for solving a problem using duhamels method
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