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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
Pulsed DC Welding Pulsed DC involves the repetitive variation in arc current from a background (low) value to a peak value. Adjustments of the pulse current time, background cu
Define and classified parallel forces Sol.: The forces, the lines of action of which are parallel to each other, are called as parallel forces. They do not meet at one point
RCC Pipe Culverts: Reinforced cement concrete pipe culverts are ideal for dealing with small discharges. The advantages are : (a) They are very economical, since a circula
The drawbacks of WFM technique have been overcome Domain While no representation can describe all possible solids, a representation should be able to represent a useful se
unstable governors
A copper tube 1.2 m long, has 80mm internal diameter and 2 mm wall thickness. It has closed ends, and is filled with water under pressure. What will be the alteration of pressure i
write a VB programme that compute the binary ordering algorithm for unlimited number of machines and parts
Inspection of Tyres STEPS Both the tyres are checked for free rotation. Loose spokes are to be tightened. At the same time it is checked that the tyre is not dam
Step s for Solving Problem for Finding Maximum Power: 1. Use formula stress (σ) = force (Maximum Tension)/Area Where; Area = b.t that is, T max = σ.b.t 2. Unit mass (
The Classical Job Shop Scheduling Problem (Jsp) A job shop scheduling problem occupies the determination of beginning time for all operations in a finite and specif
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