Work-power-energy, Mechanical Engineering

Assignment Help:

 

Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds is

A 26.6 j

B 3.3 j

C 16 j

D 32 j

Solution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)


Related Discussions:- Work-power-energy

Shear force and bending moment, question no 2,page no 84 of strenght of mat...

question no 2,page no 84 of strenght of materials by G H Ryder

State - thermodynamics, STATE - Thermodynamics: The State of system is...

STATE - Thermodynamics: The State of system is its condition or configuration described in detail. State is the condition of the system which is identified by thermodynamic

Working principle of carburettor , Working Principle of Carburettor : All ...

Working Principle of Carburettor : All carburettors work on one basic principle, the venturi. A venturi is a very simple device that changes air pressure by changing the velocity

Dynamically equivalent link-fluctuation of the energy, Dynamically Equivale...

Dynamically Equivalent Link: this is link that has point masses at two points such that (a) overall mass is same, (b) centre of gravity is at the similar position, and (c) mass m

What is the maximum load the spring may carry, What is the maximum load the...

What is the maximum load the spring may carry: Any close coiled helical spring has mean diameter of 80 mm, has spring constant of 100 kN/m. It contains 10 coils. The maximum s

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd