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Suppose that a process scheduling algorithm favors those processes that have used the least processor time in the recent past. Why will this algorithm favour I/O- bound processes, but not starve CPU-bound processes?
Ans: This will favor the I/O-bound programs due to the relatively short CPU burst request through them; though, the CPU-bound programs will not starve since I/O- bound programs will relinquish the CPU relatively frequently to do their I/O.
How can i made Carnot engine
Direct Mapping: In this particular technique, block j of the primary memory maps onto block j modulo 128 of the cache. The primary memory blocks 0,128,256,...is loaded
Program counter and Stack pointer all have 16 bits.
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Convert (177.25) 10 to octal Ans. 177.25) 10 = ( ) 8 Firstly we take integer part Hence (177) 10 = (261) 8 Now as 0.25 x 8 = 2.00 and 0.00 x 8 = 0 Therefor
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