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Why does Ethernet specify a minimum frame size.
Ethernet frame gives a minimum frame size of 46 bytes. Whereas a data field of zero byte is legal, this causes a problem. While a transceiver detects a collision, this truncates the current frame that means that stray bits and pieces of frames show on the cable all the time. To make this easier to distinguish valid frames from garbage, Ethernet gives that valid frame should be at least 64 bytes long from destination address to checksum. If data portion of frame is less, the pad field is used to fill out the frame to the minimum size.
Explain the relationship amongst Translated address and Linked address. Translated address: Address assigned through the translator Linked address: Address assigned
what is java
Add 20 and (-15) using 2's complement ? Ans. Addition of 20 and (-15) by using 2's complement as (20) 10 = 1 0 1 0 0 (16
How the at-user command serves mainly in lists? The AT USER-COMMAND event serves mostly to handle own function codes. In this case, you should make an individual interface wit
Explain the Acceptance and Request Determination As we have learned, much of the overhead in client-server interaction occurs in the CSInteface, either client or server. It is
Q. Explain logical shift Micro-operations? In logical shift data entering by serial input to left most or right most flip-flop (which depends on right or left shift operations
Q. Types of messages? The messages can be of many types. A specific field of all messages may be reserved to signify message type. The message passing primitives are like thi
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Design a 8 to 1 multiplexer by using the fourvariable function given by F(A, B, C, D) = ∑ m(0,1,3,4,8,9,15). Ans. Design of 8 to 1 Multiplexer: It is a four-variable function a
Q. Prove using Boolean Algebra 1. AB + AC + BC' = AC + BC' 2. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A 3. (A+B) (A'+B'+C) + AB = A+B 4. A'C + A'B + AB'C + BC = C + A'B
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