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Why does Ethernet specify a minimum frame size.
Ethernet frame gives a minimum frame size of 46 bytes. Whereas a data field of zero byte is legal, this causes a problem. While a transceiver detects a collision, this truncates the current frame that means that stray bits and pieces of frames show on the cable all the time. To make this easier to distinguish valid frames from garbage, Ethernet gives that valid frame should be at least 64 bytes long from destination address to checksum. If data portion of frame is less, the pad field is used to fill out the frame to the minimum size.
A program is backward compatible if it can use files from an older version of itself. For a file saved in the program to be backward compatible, it must be possible to open the fil
It speeds execution of distributed applications. It runs on dissimilar platforms. It time independent. No loss for msg delivery i.e. guarantee delivery.
Explain DOS function call with one illustration DOS function call In order to use DOS function calls, always place function number into register AH and load all other re
What is line option explicit Line explicit function makes the compiler to recognize all the variables which are not particular by the dim statement. This command significantly
ISDN handles data pertaining to? ISDN handles data pertaining to all digital services.
What are the central interfaces of the R/3 system? There are three central interfaces:- Presentation Interface. Database Interface. Operating system Interface.
Explain Classless Inter-Domain Routing. It is a new addressing scheme for the internet that permits for more efficient allocation of IP addresses than old class A, B and C addr
Explain Shadow Copy Scheme in detail.
Security features used in Client-Server types of network are as follows : i) Digital Signatures ii) Encryption / Decryption iii) Secure Socket Layer (SSL) iv) Firewa
Define rotational latency and disk bandwidth. Rotational latency is the additional time waiting for the disk to rotate the desired sector to the disk head. The disk bandwidth i
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