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Why does Ethernet specify a minimum frame size.
Ethernet frame gives a minimum frame size of 46 bytes. Whereas a data field of zero byte is legal, this causes a problem. While a transceiver detects a collision, this truncates the current frame that means that stray bits and pieces of frames show on the cable all the time. To make this easier to distinguish valid frames from garbage, Ethernet gives that valid frame should be at least 64 bytes long from destination address to checksum. If data portion of frame is less, the pad field is used to fill out the frame to the minimum size.
In 32bit IP Addressing scheme all 1's represent? All 1's represent limited broadcast in 32 bit IP Addressing scheme.
Conversioin of the decimal number 82.67 into Octal number ? Ans. The binary equivalent is (1010010.10101011) 2 of decimal number 82.67. After that convert each 3-bit binary in
What are the differences between SIMULATION and SYNTHESIS Simulation synthesis Simulation is used to verify functionality of the circuit.. a) Functional Simulation:stud
2. The Turing test has often been incorrectly interpreted as being a test of whether or not a person could distinguish between responses from a computer and responses from a person
Q. (192.8)10 - (AE.E)16 = (X)8, Find value of x. Use 8's complement method. Q. Write first 10 numbers in the base 4. Q. Explain Error-Detection code & Error-correction code w
Z80 STATUS FLAGS
Perform multiplication with showing the contents of accumulator, B register and Y register during each step. (Accumulator, B, Y are 4-bit registers) B=06 Y=02
Determine the equivalent Gray code for decimal number 6 ? Ans. The equivalent Gray code for decimal number 6 is 0101 Because the Decimal number 6 is equivalent to binary nu
Design a counter modulo 4 (sequential circuit with two flip-flops and one input U) which work like that: 1. When U=0, the state of the flip-flop does not change. 2. Whe
How many address bits are required to represent a 32 K memory ? Ans. 32K = 25 x 210 = 215, Hence 15 address bits are needed; Only 16 bits can address this.
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