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We perform load testing once we are completed with interface (GUI) testing. Modern system architectures are large and difficult. Whereas one user testing primarily on functionality and user interface of a system component, application testing focuses on performance and reliability of an whole system. For example, a typical application-testing scenario may depict 1000 users logging in at the same time to a system. This gives rise to issues such as what is the response time of the system, does it crash, will it go with different software applications and platforms, can it hold so a lot of hundreds and thousands of users, etc. This is when we set do load and performance testing.
Q. How can we Resize Layout Cells? To precisely design a page, you can set size of cells you add in a document. You can reposition cells in the page as well. 1. Click o
Which scheduling policy is most suitable for a time-shared operating system? Ans. Round-Robin scheduling policy is most appropriate for a time-shared operating system.
Diffrentiate programming tools and authoring tools Distinction between programming tools and authoring tools is not at first obvious. Though, authoring tools require less techn
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Problem: Develop three sub-systems namely Staff Profiling System, Inventory Management System and Time-tabling systems. (a) Show about any three design patterns you have us
Q. Example on Passing Parameters through Stack? PROGRAM: Version 3 DATA_SEG SEGMENT BCD DB 25h; Storage for BCD test value BIN
With the help of a truth table explain the working of a half subtractor. Draw the logic diagram using gates. Ans: Half Subtractor: For the subtraction of B (subtrahend) f
Determine the equivalent Gray code for decimal number 6 ? Ans. The equivalent Gray code for decimal number 6 is 0101 Because the Decimal number 6 is equivalent to binary nu
What is the purpose of IOP. The purpose of IOP is to given an independent path way for transfer of information among external and internal memory.
DETERMINE ANALYTICALY IF THE SIGNAL IS PERIODIC OR NOT - X[n] = 4Cos(Pi n)
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