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Q. The half life period of 84Po218 is 3 minutes. What percentage of the sample has decayed in 15 minutes?
1 HLP = 3 minutes
In 15 minutes, there are 3 HLPs
The remaining part of radioactive substance = (½)3
Therefore The percentage of remaining part of radioactive substance = (½)3 X 100%
= 12.5 %
Decayed percentage = 100 - 12.5 = 87.5 %
a) A uniform mild steel ring has a diameter of 50mm and a cross-sectional area of 1cm 2 . Determine the mmf essential to produce a flux of 50µWb in the ring. (b) I
Q. State Coulombs law in electrostatics? Coulomb's law declares that the force of attraction or repulsion between two point charges is directly proportional to the product of t
#WHAT IS THE PRINCIPLE OF REGULATOR?
how to calculate wave function of particle?
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