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QUESTION
(a) Suppose that you have been assigned to re-engineer the existing systems for a company. Do you think that design patterns can be applied to these existing systems? Justify your answer.
(b) What are three reasons that cause requirements to change?
(c) What are the three reasons for using design patterns?
(d) What makes a Pattern a Pattern?
(e) What does Alexander means by the following statement "But it is impossible to form anything which has the character of nature by adding preformed parts.
Phong shading OR Normal Vector Interpolation Shading In Gouraud shading we were doing direct interpolation of intensities although a more exact method for rendering a polygon
Q. What Colour depths are basically used? Basically the number of colours are an exponential power of 2 as for Colour Depth n, colours can be showed. The most popular colour mo
Frame Buffers - Graphics Hardware The storage region in a raster scan display system is set as a two-dimensional table. All row-column entry stores information as brightness
Reflection and Shear There are a few important transformations which are not primitive in the sense that they can be expressed as compositions of translation, rotation and scal
How we create virtual reality images for use on a computer system When a virtual tour of, for instance, a house is shown on a website the images need to be first created and th
Suppose here, one allows 256 depth value levels to be employed. Approximately how much memory would a 512x512 pixel display necessitate to store z-buffer? Solution : A system w
In contrast to depth-buffer method, here we identify one surface at one time, scan-line method deals along with multiple surfaces. Since it processes each scan-line at one time, al
Amiga - Hardware for computer animation Originally owned through Commodore, Amiga computers have conduct a position in the computer animation industry for many years. This is
Draw and explain the diagram of a Raster scan system with a display processor. Explain each unit of the diagram.
To prove: P (u = 0) = p0 Solution : = p 0 B n,0 (u) + p 1 B n, 1 (u) +...... + p n B n, n (u)...............(1) B n,i (u) = n c i u i (1 - u) n-i B n,0
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